2^x^2-3x-4=2^0

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Solution for 2^x^2-3x-4=2^0 equation: 



2^x^2-3x-4=2^0

We move all terms to the left:

2^x^2-3x-4-(2^0)=0

We add all the numbers together, and all the variables

-3x+2^x^2-5=0

We move all terms containing x to the left, all other terms to the right

-3x+2^x^2=5

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